There are `n`

buildings in a line. You are given an integer array `heights`

of size `n`

that represents the heights of the buildings in the line.

The ocean is to the right of the buildings. A building has an ocean view if the building can see the ocean without obstructions. Formally, a building has an ocean view if all the buildings to its right have a **smaller** height.

Return a list of indices **(0-indexed)** of buildings that have an ocean view, sorted in increasing order.

**Example 1:**

Input:heights = [4,2,3,1]Output:[0,2,3]Explanation:Building 1 (0-indexed) does not have an ocean view because building 2 is taller.

**Example 2:**

Input:heights = [4,3,2,1]Output:[0,1,2,3]Explanation:All the buildings have an ocean view.

**Example 3:**

Input:heights = [1,3,2,4]Output:[3]Explanation:Only building 3 has an ocean view.

**Example 4:**

Input:heights = [2,2,2,2]Output:[3]Explanation:Buildings cannot see the ocean if there are buildings of thesameheight to its right.

**Constraints:**

`1 <= heights.length <= 10`

^{5}`1 <= heights[i] <= 10`

^{9}

Solution1:

```
class Solution(object):
def findBuildings(self, heights):
"""
:type heights: List[int]
:rtype: List[int]
"""
if not heights:
return []
output = [len(heights)-1]
j = len(heights)-2
largest = heights[-1]
while j >= 0:
if heights[j] > largest:
output.append(j)
largest = heights[j]
j -= 1
return output[::-1]
```

Solution2:

```
class Solution:
def findBuildings(self, heights):
answer = []
maxHeight = 0
for i in range(len(heights) - 1, -1, -1):
if heights[i] > maxHeight:
answer.append(i)
maxHeight = heights[i]
return reversed(answer)
```