# 937. Reorder Data in Log Files

You are given an array of `logs`. Each log is a space-delimited string of words, where the first word is the identifier.

There are two types of logs:

• Letter-logs: All words (except the identifier) consist of lowercase English letters.
• Digit-logs: All words (except the identifier) consist of digits.

Reorder these logs so that:

1. The letter-logs come before all digit-logs.
2. The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.
3. The digit-logs maintain their relative ordering.

Return the final order of the logs.

Example 1:

```Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
Explanation:
The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".
```

Example 2:

```Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]
```

Constraints:

• `1 <= logs.length <= 100`
• `3 <= logs[i].length <= 100`
• All the tokens of `logs[i]` are separated by a single space.
• `logs[i]` is guaranteed to have an identifier and at least one word after the identifier.

Wrong Solution

``````class Solution:
def reorderLogFiles(self, logs):
return sorted(logs, key = lambda l: '0'+" ".join(l.split()[1:])+l.split() if l.split().isalpha() else '1')``````

Probably not the most efficient because we split the same line multiple times, but it looks like Python does it pretty efficiently …

Using the standard approach, with a lambda function:

check the l element, if it’s numeric, return `'0' + l[1:] + l`, otherwise returns `'1'`.

That way the text entries will be shown first sorted based on `l[1:] + l` and the other entries (presumably numeric) will follow in the original order.

Solution

``````class Solution:
def reorderLogFiles(self, logs):
l = filter(lambda l: l[l.find(" ") + 1].isalpha(), logs)
d = filter(lambda l: l[l.find(" ") + 1].isdigit(), logs)
return sorted(l, key = lambda x: (x[x.find(" "):], x[:x.find(" ")])) + list(d)``````
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